Example 1: Ball-drawing problem in probability. A bag contains 5 red balls and 3 white balls. Two balls are drawn at random; what is the probability of getting exactly one red and one white ball? First, the total number of possible outcomes is the number of ways to choose 2 balls out of 8 without regard to order—a combination problem calculated as C(8,2) = 28. Next, the number of favorable outcomes is the number of ways to choose 1 red ball from 5 (C(5,1) = 5) and 1 white ball from 3 (C(3,1) = 3). By the multiplication principle, there are 5 × 3 = 15 favorable cases. Therefore, the probability is 15/28.
Example 2: Line-up and seating arrangement. Five people are lining up, with the condition that person A and person B must stand together. Treat A and B as a single unit ("bonded"), resulting in 4 units to permute, giving P(4,4) = 24 arrangements. Within the bonded unit, A and B can switch places in P(2,2) = 2 ways. By the multiplication principle, the total number of valid arrangements is 24 × 2 = 48. This illustrates the application of permutations where order matters.
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